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Date November 2017 Marks available 3 Reference code 17N.1.SL.TZ0.T_14
Level Standard Level Paper Paper 1 Time zone Time zone 0
Command term Find Question number T_14 Adapted from N/A

Question

A function f is given by f ( x ) = 4 x 3 + 3 x 2 3 ,   x 0 .

Write down the derivative of f .

[3]
a.

Find the point on the graph of f at which the gradient of the tangent is equal to 6.

[3]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

12 x 2 6 x 3 or equivalent     (A1)(A1)(A1)     (C3)

 

Note:     Award (A1) for 12 x 2 , (A1) for 6 and (A1) for 1 x 3 or x 3 . Award at most (A1)(A1)(A0) if additional terms seen.

 

[3 marks]

a.

12 x 2 6 x 3 = 6     (M1)

 

Note:     Award (M1) for equating their derivative to 6.

 

( 1 ,   4 ) OR x = 1 ,   y = 4     (A1)(ft)(A1)(ft)     (C3)

 

Note:     A frequent wrong answer seen in scripts is ( 1 ,   6 ) for this answer with correct working award (M1)(A0)(A1) and if there is no working award (C1).

 

[3 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 5—Calculus » SL 5.1—Introduction of differential calculus
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Topic 5—Calculus » SL 5.3—Differentiating polynomials, n E Z
Topic 5—Calculus » SL 5.4—Tangents and normal
Topic 2—Functions » SL 2.5—Modelling functions
Topic 2—Functions
Topic 5—Calculus

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