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Date May 2022 Marks available 5 Reference code 22M.1.SL.TZ1.4
Level Standard Level Paper Paper 1 Time zone Time zone 1
Command term Find Question number 4 Adapted from N/A

Question

Three towns, A, B and C are represented as coordinates on a map, where the x and y axes represent the distances east and north of an origin, respectively, measured in kilometres.

Town A is located at (6, 1) and town B is located at (8, 6). A road runs along the perpendicular bisector of [AB]. This information is shown in the following diagram.

Find the equation of the line that the road follows.

[5]
a.

Town C is due north of town A and the road passes through town C.

Find the y-coordinate of town C.

[2]
b.

Markscheme

midpoint (1, 2.5)           A1

mAB=6--18--6=12           (M1)A1


Note: Accept equivalent gradient statements including using midpoint.

 

m=-2           M1


Note: Award M1 for finding the negative reciprocal of their gradient.


y-2.5=-2x-1  OR  y=-2x+92  OR  4x+2y-9=0           A1

 

[5 marks]

a.

substituting x=-6 into their equation from part (a)           (M1)

y=-2-6+92

y=16.5           A1


Note: Award M1A0 for -6, 16.5 as their final answer.

 

[2 marks]

b.

Examiners report

A large proportion of candidates seemed to be well drilled into finding the gradient of a line and the subsequent gradient of the normal. But without finding the coordinates of the midpoint of AB, no more marks were gained.

 

a.

Many candidates worked out the value of y correctly (or “correct” following the value they found in part (a)) but then incorrectly gave their answer as a coordinate pair.

b.

Syllabus sections

Topic 2—Functions » SL 2.1—Equations of straight lines, parallel and perpendicular
Show 26 related questions
Topic 3—Geometry and trigonometry » SL 3.5—Intersection of lines, equations of perpendicular bisectors
Topic 2—Functions
Topic 3—Geometry and trigonometry

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