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Date May 2022 Marks available 3 Reference code 22M.1.SL.TZ2.13
Level Standard Level Paper Paper 1 Time zone Time zone 2
Command term Determine Question number 13 Adapted from N/A

Question

Juliana plans to invest money for 10 years in an account paying 3.5% interest, compounded annually. She expects the annual inflation rate to be 2% per year throughout the 10-year period.

Juliana would like her investment to be worth a real value of $4000, compared to current values, at the end of the 10-year period. She is considering two options.

Option 1: Make a one-time investment at the start of the 10-year period.

Option 2: Invest $1000 at the start of the 10-year period and then invest $x into the account 
                at the end of each year (including the first and last years).

For option 1, determine the minimum amount Juliana would need to invest. Give your answer to the nearest dollar.

[3]
a.

For option 2, find the minimum value of x that Juliana would need to invest each year. Give your answer to the nearest dollar.

[3]
b.

Markscheme

METHOD 1 (with FV=4000)

EITHER

N=10
I=1.5
FV=4000
P/Y=1
C/Y=1              (A1)(M1)


Note: Award A1 for 3.5-2= 1.5 seen and M1 for all other entries correct.


OR

4000=A1+0.01510              (A1)(M1)


Note: Award A1 for 1.5 or 0.015 seen, M1 for attempt to substitute into compound interest formula and equating to 4000.


THEN

PV= $3447            A1


Note: Award A0 if not rounded to a whole number or a negative sign given.

 

METHOD 2 – (With FV including inflation)

calculate FV with inflation

4000×1.0210              (A1)

=4875.977


EITHER

4000×1.0210=PV×1.03510                (M1)


OR

N=10
I=3.5
FV=4875.977
P/Y=1
C/Y=1                (M1)


Note: Award M1 for their FV and all other entries correct.


THEN

PV= $3457            A1


Note: Award A0 if not rounded to a whole number or a negative sign given.

 

METHOD 3 – (Using formula to calculate real rate of return)

(real rate of return =) 1.47058%              (A1)


EITHER

4000=PV×1.014705810              (A1)


OR

N=10
I=1.47058
FV=4000
P/Y=1
C/Y=1                (M1)


Note: Award M1 for all entries correct.


THEN

PV= $3457            A1

 

[3 marks]

a.

METHOD 1 (Finding the future value of the investment using PV from part (a))

N=10
I=3.5
PV=3446.66 (from Method 1)  OR  3456.67 (from Methods 2, 3)
P/Y=1
C/Y=1              (M1)


Note: Award M1 for interest rate 3.5 and answer to part (a) as PV.


FV= $4861.87   OR   $4875.97              (A1)

so payment required (from TVM) will be $294   OR  $295              A1


Note: Award A0 if a negative sign given, unless already penalized in part (a).

 

METHOD 2 – (Using FV)

N=10
I=3.5
PV=-1000
FV=4875.977
P/Y=1
C/Y=1              (A1)(M1)


Note: Award A1 for I=3.5 and FV=±4875.977, M1 for all other entries correct and opposite PV and FV signs.


PMT=  $295   295.393              A1


Note: Correct 3sf answer is 295, however accept an answer of 296 given that the context supports rounding up. Award A0 if a negative sign given, unless already penalized in part (a).

 

[3 marks]

b.

Examiners report

Very few candidates appeared to be familiar with real rate of return on an investment and attempted the question by ignoring the inflation rate. There was a mix of candidates who attempted to use the financial app on their graphic display calculator and those who attempted to use the compound interest formula, both of which are accepted methods. The preferred method of the IB for calculating the real rate of return is by simply subtracting the inflation rate from the nominal interest rate, however the exact formula is of course accepted too.

a.

Was very poorly done, both in recognition of an appropriate future value with inflation and realizing that PV and FV must have opposite signs when using the financial app on their graphic display calculator. In both parts of the question, there seemed to be little consideration as to the appropriateness of the answers, and often unreasonable answers were presented.

b.

Syllabus sections

Topic 1—Number and algebra » SL 1.4—Financial apps – compound interest, annual depreciation
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