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Question 19N.2.hl.TZ0.3d(iii)

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Date November 2019 Marks available [Maximum mark: 1] Reference code 19N.2.hl.TZ0.3d(iii)
Level hl Paper 2 Time zone TZ0
Command term Explain Question number d(iii) Adapted from N/A
d(iii).
[Maximum mark: 1]
19N.2.hl.TZ0.3d(iii)

Propene is an important starting material for many products. The following shows some compounds which can be made from propene, C3H6.


Propene (C3H6) → C3H7Cl → C3H8O → C3H6O

(d(iii))

Explain why the 1H NMR spectrum of C3H6O, produced in (d)(i), shows only one signal.

[1]

Markscheme

only one hydrogen environment
OR
methyl groups symmetrical «around carbonyl group» ✔

NOTE: Accept “all hydrogens belong to methyl groups «which are in identical positions»”.

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