DP Chemistry (last assessment 2024)
Question 19N.2.hl.TZ0.6e(i)
| Date | November 2019 | Marks available | [Maximum mark: 1] | Reference code | 19N.2.hl.TZ0.6e(i) |
| Level | hl | Paper | 2 | Time zone | TZ0 |
| Command term | Calculate | Question number | e(i) | Adapted from | N/A |
e(i).
[Maximum mark: 1]
19N.2.hl.TZ0.6e(i)
Copper forms two chlorides, copper(I) chloride and copper(II) chloride.
Copper(I) chloride undergoes a disproportionation reaction, producing copper(II) chloride and copper.
2Cu+ (aq) → Cu (s) + Cu2+ (aq)
(e(i))
Calculate the cell potential at 298 K for the disproportionation reaction, in V, using section 24 of the data booklet.
[1]
Markscheme
Eθ = «+0.52 – 0.15 = +» 0.37 «V» ✔
