DP Chemistry (last assessment 2024)

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Question 21N.2.hl.TZ0.11b

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Date November 2021 Marks available [Maximum mark: 1] Reference code 21N.2.hl.TZ0.11b
Level hl Paper 2 Time zone TZ0
Command term Calculate Question number b Adapted from N/A
b.
[Maximum mark: 1]
21N.2.hl.TZ0.11b

50.00 cm3 of 0.75 mol dm−3 sodium hydroxide was added in 1.00 cm3 portions to 22.50 cm3 of 0.50 mol dm−3 chloroethanoic acid.

(b)

The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.

[1]

Markscheme

«pOH = –log(0.362) = 0.441»

«pH = 14.000 – 0.441 =» 13.559 ✔