DP Chemistry (last assessment 2024)

Question 22M.1.hl.TZ1.21

Date	May 2022	Marks available	[Maximum mark: 1]	Reference code	22M.1.hl.TZ1.21
Level	hl	Paper	1	Time zone	TZ1
Command term	Derive	Question number	21	Adapted from	N/A

21.

[Maximum mark: 1]

22M.1.hl.TZ1.21

What is the activation energy according to the following plot of the linear form of the Arrhenius equation?

Arrhenius equation: $k = A e^{\frac{- E a}{R T}}$ .

A. $E_{a} = \frac{2 \times 8.31}{0.06}$

B. $E_{a} = \frac{- 2 \times 8.31}{0.06}$

C. $E_{a} = e^{\frac{2 \times 8.31}{0.06}}$

D. $E_{a} = e^{\frac{- 2 \times 8.31}{0.06}}$

[1]

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Examiners report

A discriminating question in which high scoring candidates had much greater success in transforming the Arrhenius equation into the units used in the graph by taking its natural log and using the dimensions of the slope to arrive at the correct answer.

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Additional higher level (AHL)

Additional higher level (AHL) » Topic 16: Chemical kinetics » 16.1 Rate expression and reaction mechanism

Additional higher level (AHL) » Topic 16: Chemical kinetics

Question 22M.1.hl.TZ1.21

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