DP Chemistry (last assessment 2024)
Question 17N.1.hl.TZ0.4
| Date | November 2017 | Marks available | [Maximum mark: 1] | Reference code | 17N.1.hl.TZ0.4 |
| Level | hl | Paper | 1 | Time zone | TZ0 |
| Command term | Question number | 4 | Adapted from | N/A |
4.
[Maximum mark: 1]
17N.1.hl.TZ0.4
A compound with Mr = 102 contains 58.8 % carbon, 9.80 % hydrogen and 31 % oxygen by mass.
What is its molecular formula?
Ar: C = 12.0; H = 1.0; O = 16.0
A. C2H14O4
B. C3H4O4
C. C5H10O2
D. C6H14O
[1]
Markscheme
C