DP Chemistry (last assessment 2024)

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Question 18M.2.hl.TZ2.2d.ii

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Date May 2018 Marks available [Maximum mark: 2] Reference code 18M.2.hl.TZ2.2d.ii
Level hl Paper 2 Time zone TZ2
Command term Calculate Question number d.ii Adapted from N/A
d.ii.
[Maximum mark: 2]
18M.2.hl.TZ2.2d.ii

Graphing is an important tool in the study of rates of chemical reactions.

(d.ii)

Calculate the pH of 0.100 mol dm−3 aqueous ethanoic acid.

Ka = 1.74 × 10−5

[2]

Markscheme

K a = 1.74 × 10 − 5 = [ H + ] 2 0.10

OR

[H+] = 1.32 × 10–3 «mol dm–3»

«pH =» 2.88

 

Accept [2] for correct final answer.

[2 marks]

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