DP Chemistry (last assessment 2024)
Question 18M.2.hl.TZ2.4
Date | May 2018 | Marks available | [Maximum mark: 4] | Reference code | 18M.2.hl.TZ2.4 |
Level | hl | Paper | 2 | Time zone | TZ2 |
Command term | Calculate, Determine, Formulate | Question number | 4 | Adapted from | N/A |
4.
[Maximum mark: 4]
18M.2.hl.TZ2.4
(a)
In acidic solution, bromate ions, BrO3−(aq), oxidize iodide ions, I−(aq).
BrO3−(aq) + 6H+(aq) + 6e− Br−(aq) + 3H2O(l)
2I−(aq) I2(s) + 2e−
Formulate the equation for the redox reaction.
[1]
Markscheme
BrO3–(aq) + 6H+(aq) + 6I–(aq) Br–(aq) + 3I2(s) + 3H2O(l)
Accept → for .
[1 mark]
(b)
The change in the free energy for the reaction under standard conditions, ΔGΘ, is −514 kJ at 298 K.
Determine the value of EΘ, in V, for the reaction using sections 1 and 2 of the data booklet.
[2]
Markscheme
n = 6
«ΔGΘ = –nFEΘ»
«» 0.888 «V»
[2 marks]

(c)
Calculate the standard electrode potential, in V, for the BrO3−/Br− reduction half‑equation using section 24 of the data booklet.
[1]
Markscheme
«EΘ = EΘ(BrO3–/Br–) – EΘ(I2/I–)»
«EΘ(BrO3–/Br–) = EΘ + EΘ(I2/I–) = 0.888 + 0.54 =» «+» 1.43 «V»
[1 mark]
