DP Chemistry (last assessment 2024)

Question 18M.1.sl.TZ1.14

Date	May 2018	Marks available	[Maximum mark: 1]	Reference code	18M.1.sl.TZ1.14
Level	sl	Paper	1	Time zone	TZ1
Command term	Derive	Question number	14	Adapted from	N/A

14.

[Maximum mark: 1]

18M.1.sl.TZ1.14

What is the enthalpy of combustion of butane in kJ mol⁻¹?

2C₄H₁₀(g) + 13O₂(g) → 8CO₂(g) + 10H₂O(l)

$\begin{array}{*{20}{l}} {{\text{C(s)}} + {{\text{O}}_2}{\text{(g)}} \to {\text{C}}{{\text{O}}_2}{\text{(g)}}}&{\Delta H = x{\text{ kJ}}} \\ {{{\text{H}}_2}{\text{(g)}} + \frac{{\text{1}}}{2}{{\text{O}}_2}{\text{(g)}} \to {{\text{H}}_2}{\text{O(l)}}}&{\Delta H = y{\text{ kJ}}} \\ {4{\text{C(s)}} + {\text{5}}{{\text{H}}_2}{\text{(g)}} \to {{\text{C}}_4}{{\text{H}}_{{\text{10}}}}{\text{(g)}}}&{\Delta H = z{\text{ kJ}}} \end{array}$

A. 4x + 5y − z

B. 4x + 5y + z

C. 8x + 10y − 2z

D. 8x + 5y + 2z

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Core » Topic 5: Energetics/thermochemistry » 5.2 Hess’s Law

Core » Topic 5: Energetics/thermochemistry

Question 18M.1.sl.TZ1.14

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