Question 19M.2.hl.TZ2.1d(iii)
Date | May 2019 | Marks available | [Maximum mark: 3] | Reference code | 19M.2.hl.TZ2.1d(iii) |
Level | hl | Paper | 2 | Time zone | TZ2 |
Command term | Explain | Question number | d(iii) | Adapted from | N/A |
Ethyne, C2H2, reacts with oxygen in welding torches.
Product B, CH3CHO, can also be synthesized from ethanol.
Explain why product B is water soluble.
[3]
Any three of:
has an oxygen/O atom with a lone pair [✔]
that can form hydrogen bonds/H-bonds «with water molecules» [✔]
hydrocarbon chain is short «so does not disrupt many H-bonds with water molecules» [✔]
«large permanent» dipole-dipole interactions with water [✔]
Candidates did not understand that they must mention the IMF responsible for the solubility. Most candidates explained the polarity of the aldehyde and water but did not mention that this results in permanent dipole-dipole interactions; many did mention H-bonding. The mention of the lone pair on O atom and short hydrocarbon chain were very rare.
