DP Chemistry (last assessment 2024)
Question 19N.2.hl.TZ0.d(ii)
| Date | November 2019 | Marks available | [Maximum mark: 2] | Reference code | 19N.2.hl.TZ0.d(ii) |
| Level | hl | Paper | 2 | Time zone | TZ0 |
| Command term | Explain | Question number | d(ii) | Adapted from | N/A |
d(ii).
[Maximum mark: 2]
19N.2.hl.TZ0.d(ii)
Propene is an important starting material for many products. The following shows some compounds which can be made from propene, C3H6.
Propene (C3H6) → C3H7Cl → C3H8O → C3H6O
Explain why the compound C3H8O, produced in (a)(iv), has a higher boiling point than compound C3H6O, produced in d(i).
[2]
Markscheme
C3H8O/propan-2-ol: hydrogen-bonding AND C3H6O/propanone: no hydrogen bonding/«only» dipole–dipole/dispersion forces ✔
hydrogen bonding stronger «than dipole–dipole» ✔
