DP Chemistry (last assessment 2024)

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Question 19N.2.hl.TZ0.6e(iii)

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Date November 2019 Marks available [Maximum mark: 1] Reference code 19N.2.hl.TZ0.6e(iii)
Level hl Paper 2 Time zone TZ0
Command term Calculate Question number e(iii) Adapted from N/A
e(iii).
[Maximum mark: 1]
19N.2.hl.TZ0.6e(iii)

Copper forms two chlorides, copper(I) chloride and copper(II) chloride.

Copper(I) chloride undergoes a disproportionation reaction, producing copper(II) chloride and copper.

2Cu+ (aq) → Cu (s) + Cu2+ (aq)

(e(iii))

Calculate the standard Gibbs free energy change, ΔGθ, to two significant figures, for the disproportionation at 298 K. Use your answer from (e)(i) and sections 1 and 2 of the data booklet.

[1]

Markscheme

ΔGθ = «−nFE = −1 mol × 96 500 C Mol–1 × 0.37 V=» −36 000 J/−36 kJ ✔

 

NOTE: Accept “−18 kJ mol–1 «per mole of Cu+»”.

Do not accept values of n other than 1.

Apply SF in this question.

Accept J/kJ or J mol−1/kJ mol−1 for units.

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