DP Chemistry (last assessment 2024)
Question 19N.2.sl.TZ0.d(ii)
| Date | November 2019 | Marks available | [Maximum mark: 2] | Reference code | 19N.2.sl.TZ0.d(ii) |
| Level | sl | Paper | 2 | Time zone | TZ0 |
| Command term | Explain | Question number | d(ii) | Adapted from | N/A |
d(ii).
[Maximum mark: 2]
19N.2.sl.TZ0.d(ii)
The following shows some compounds which can be made from ethene, C2H4.
ethene (C2H4) → C2H5Cl → C2H6O → C2H4O
Explain why the compound C2H6O, produced in (b), has a higher boiling point than compound C2H4O, produced in d(i).
[2]
Markscheme
C2H6O/ethanol: hydrogen-bonding AND C2H4O/ethanal: no hydrogen-bonding/«only» dipole–dipole forces ✔
hydrogen bonding stronger «than dipole–dipole» ✔
