DP Chemistry (last assessment 2024)

Question 20N.2.hl.TZ0.1b(vi)

Date	November 2020	Marks available	[Maximum mark: 1]	Reference code	20N.2.hl.TZ0.1b(vi)
Level	hl	Paper	2	Time zone	TZ0
Command term	Deduce	Question number	b(vi)	Adapted from	N/A

b(vi).

[Maximum mark: 1]

20N.2.hl.TZ0.1b(vi)

Chlorine undergoes many reactions.

$2.67 g$ of manganese(IV) oxide was added to $200.0 {cm}^{3}$ of $2.00 mol {dm}^{- 3} HCl$ .

${MnO}_{2} (s) + 4 HCl (aq) \to {Cl}_{2} (g) + 2 H_{2} O (l) + {MnCl}_{2} (aq)$

(b(vi))

Deduce, referring to oxidation states, whether ${MnO}_{2}$ is an oxidizing or reducing agent.

[1]

Markscheme

oxidizing agent AND oxidation state of $Mn$ changes from $+ 4$ to $+ 2$ /decreases ✔

Examiners report

Most candidates stated that MnO₂ is an oxidizing agent in the reaction but many did not get the mark because there was no reference to oxidation states.

Syllabus sections

Core

Core » Topic 9: Redox processes » 9.1 Oxidation and reduction

Core » Topic 9: Redox processes

Question 20N.2.hl.TZ0.1b(vi)

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