DP Chemistry (last assessment 2024)

Question 21N.2.sl.TZ0.b

Date	November 2021	Marks available	[Maximum mark: 1]	Reference code	21N.2.sl.TZ0.b
Level	sl	Paper	2	Time zone	TZ0
Command term	Determine	Question number	b	Adapted from	N/A

[Maximum mark: 1]

21N.2.sl.TZ0.b

A 4.406 g sample of a compound containing only C, H and O was burnt in excess oxygen. 8.802 g of CO₂ and 3.604 g of H₂O were produced.

Determine the molecular formula of this compound if its molar mass is 88.12 g mol⁻¹. If you did not obtain an answer in (a) use CS, but this is not the correct answer.

[1]

Markscheme

« $\frac{88.12 g {mol}^{- 1}}{44.06 g {mol}^{- 1}} = 2$ » C₄H₈O₂ ✔

C₂S₂ if CS used.

Syllabus sections

Core

Core » Topic 1: Stoichiometric relationships » 1.2 The mole concept

Core » Topic 1: Stoichiometric relationships

Question 21N.2.sl.TZ0.b

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