DP Chemistry (last assessment 2024)
Question 21N.2.hl.TZ0.b
| Date | November 2021 | Marks available | [Maximum mark: 1] | Reference code | 21N.2.hl.TZ0.b |
| Level | hl | Paper | 2 | Time zone | TZ0 |
| Command term | Calculate | Question number | b | Adapted from | N/A |
b.
[Maximum mark: 1]
21N.2.hl.TZ0.b
50.00 cm3 of 0.75 mol dm−3 sodium hydroxide was added in 1.00 cm3 portions to 22.50 cm3 of 0.50 mol dm−3 chloroethanoic acid.
The concentration of excess sodium hydroxide was 0.362 mol dm−3. Calculate the pH of the solution at the end of the experiment.
[1]
Markscheme
«pOH = –log(0.362) = 0.441»
«pH = 14.000 – 0.441 =» 13.559 ✔
