Question 22N.2.hl.TZ0.3d

Alternative 1

«$E=745 kJ mo{l}^{-1}\times \frac{1 mol}{6.02\times {10}^{23} atoms}=$» $1.24\times {10}^{-21}$ «$kJ ato{m}^{-1}$» ✔

 «$E=hv$»

«$1.24\times {10}^{-21} kJ\times \frac{1000 J}{1 kJ}=6.63\times {10}^{-34} Js\times v$»

 «$v=$» $1.87\times {10}^{15}$  «$s^{-1}$» ✔

Alternative 2

 «$E=hv$»

 «$\mathit{745}\mathit{\times }{\mathit{10}}^{\mathit{3}} J mo{l}^{\mathit{-}\mathit{1}}=\mathit{6}\mathit{.}\mathit{63}\mathit{\times }{\mathit{10}}^{\mathit{-}\mathit{34}} J s\times v$»

 «$v=$» $\mathit{1}\mathit{.}\mathit{12}\mathit{\times }{\mathit{10}}^{\mathit{39}}$  «$s^{\mathit{-}\mathit{1}}\mathit{ }mo{l}^{\mathit{-}\mathit{1}}$» ✔

 «$=\frac{1.12\times {10}^{39} s^{-1}}{6.02\times {10}^{23}}$» $=\mathit{1}\mathit{.}\mathit{87}\times {\mathit{10}}^{\mathit{15}}$  «$s^{\mathit{-}\mathit{1}}$» ✔

Award [2] for correct final answer.