DP Chemistry (last assessment 2024)

Question 17N.2.sl.TZ0.4a

Date	November 2017	Marks available	[Maximum mark: 3]	Reference code	17N.2.sl.TZ0.4a
Level	sl	Paper	2	Time zone	TZ0
Command term	Determine	Question number	a	Adapted from	N/A

[Maximum mark: 3]

17N.2.sl.TZ0.4a

Menthol is an organic compound containing carbon, hydrogen and oxygen.

(a)

Complete combustion of 0.1595 g of menthol produces 0.4490 g of carbon dioxide and 0.1840 g of water. Determine the empirical formula of the compound showing your working.

[3]

Markscheme

carbon: « $\frac{{0.4490\,{\text{g}}}}{{44.01\,{\text{g}}\,{\text{mo}}{{\text{l}}^{ - 1}}}}$ » = 0.01020 «mol» / 0.1225 «g»

hydrogen: « $\frac{{0.1840 \times 2}}{{18.02}}$ » = 0.02042 «mol» / 0.0206 «g»

oxygen: «0.1595 – (0.1225 + 0.0206)» = 0.0164 «g» / 0.001025 «mol»

empirical formula: C₁₀H₂₀O

Award [3] for correct final answer.

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Core

Core » Topic 1: Stoichiometric relationships » 1.2 The mole concept

Core » Topic 1: Stoichiometric relationships

Question 17N.2.sl.TZ0.4a

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