DP Chemistry (last assessment 2024)

Question 18M.2.hl.TZ1.e

Date	May 2018	Marks available	[Maximum mark: 2]	Reference code	18M.2.hl.TZ1.e
Level	hl	Paper	2	Time zone	TZ1
Command term	Determine	Question number	e	Adapted from	N/A

[Maximum mark: 2]

18M.2.hl.TZ1.e

The diagram shows an incomplete voltaic cell with a light bulb in the circuit.

Determine the loss in mass of one electrode if the mass of the other electrode increases by 0.10 g.

[2]

Markscheme

«moles of silver $\frac{{0.10{\text{ g}}}}{{107.87{\text{ g mo}}{{\text{l}}^{ - 1}}}}$ »

moles of magnesium $= \frac{{0.5 \times 0.10{\text{ }}\ll {\text{g}}\gg }}{{107.87{\text{ }}\ll {\text{g mo}}{{\text{l}}^{ - 1}}\gg }}$

«loss in mass of magnesium $= \frac{{24.31{\text{ g mol}} \times 0.5 \times 0.10{\text{ g}}}}{{107.87{\text{ g mo}}{{\text{l}}^{ - 1}}}} =$ » 0.011 «g»

Award [2] for correct final answer.

[2 marks]

Syllabus sections

Additional higher level (AHL)

Additional higher level (AHL) » Topic 19: Redox processes » 19.1 Electrochemical cells

Additional higher level (AHL) » Topic 19: Redox processes

Question 18M.2.hl.TZ1.e

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