DP Chemistry (last assessment 2024)

Question 18M.2.hl.TZ2.4b

Date	May 2018	Marks available	[Maximum mark: 2]	Reference code	18M.2.hl.TZ2.4b
Level	hl	Paper	2	Time zone	TZ2
Command term	Determine	Question number	b	Adapted from	N/A

[Maximum mark: 2]

18M.2.hl.TZ2.4b

(b)

The change in the free energy for the reaction under standard conditions, ΔG^Θ, is −514 kJ at 298 K.

Determine the value of E^Θ, in V, for the reaction using sections 1 and 2 of the data booklet.

[2]

Markscheme

n = 6

«ΔG^Θ = –nFE^Θ»

« ${E^\Theta } = - \frac{{\Delta {G^\Theta }}}{{{\text{n}}F}} = \frac{{514 \times {{10}^3}{\text{ J mo}}{{\text{l}}^{ - 1}}}}{{6 \times 9.65 \times {{10}^4}{\text{ C mo}}{{\text{l}}^{ - 1}}}} =$ » 0.888 «V»

[2 marks]

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Additional higher level (AHL)

Additional higher level (AHL) » Topic 19: Redox processes » 19.1 Electrochemical cells

Additional higher level (AHL) » Topic 19: Redox processes

Question 18M.2.hl.TZ2.4b

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