DP Chemistry (last assessment 2024)
Question 18M.2.hl.TZ2.a
| Date | May 2018 | Marks available | [Maximum mark: 3] | Reference code | 18M.2.hl.TZ2.a |
| Level | hl | Paper | 2 | Time zone | TZ2 |
| Command term | Determine | Question number | a | Adapted from | N/A |
a.
[Maximum mark: 3]
18M.2.hl.TZ2.a
Enthalpy changes depend on the number and type of bonds broken and formed.
Hydrogen gas can be formed industrially by the reaction of natural gas with steam.
CH4(g) + H2O(g) → 3H2(g) + CO(g)
Determine the enthalpy change, ΔH, for the reaction, in kJ, using section 11 of the data booklet.
Bond enthalpy for C≡O: 1077 kJ mol−1
[3]
Markscheme
bonds broken: 4(C–H) + 2(H–O)/4(414) + 2(463)/2582 «kJ»
bonds made: 3(H–H) + C≡O/3(436) + 1077/2385 «kJ»
ΔH «= ΣBE(bonds broken) – ΣBE(bonds made) = 2582 – 2385» = «+» 197 «kJ»
Award [3] for correct final answer.
Award [2 max] for –197 «kJ».
[3 marks]
