DP Chemistry (last assessment 2024)

Question 18N.2.sl.TZ0.b

Date	November 2018	Marks available	[Maximum mark: 2]	Reference code	18N.2.sl.TZ0.b
Level	sl	Paper	2	Time zone	TZ0
Command term	Calculate	Question number	b	Adapted from	N/A

[Maximum mark: 2]

18N.2.sl.TZ0.b

Propan-2-ol is a useful organic solvent.

Calculate the number of hydrogen atoms in 1.00 g of propan-2-ol.

[2]

Markscheme

« $\frac{{1.00\,{\text{g}}}}{{\left( {12.01 \times 3 + 1.01 \times 8 + 16.00} \right)\,{\text{g}}\,{\text{mo}}{{\text{l}}^{ - 1}}}} =$ » 0.0166 «mol CH₃CH(OH)CH₃» ✔

«0.0166 mol × 6.02 × 10²³ molecules mol⁻¹ × 8 atoms molecule⁻¹ =» 8.01 × 10²² «atoms of hydrogen» ✔

Accept answers in the range 7.99 × 10²²to 8.19 × 10²².

Award [2] for correct final answer.

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Core

Core » Topic 1: Stoichiometric relationships » 1.2 The mole concept

Core » Topic 1: Stoichiometric relationships

Question 18N.2.sl.TZ0.b

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