DP Chemistry (last assessment 2024)
Question 18N.2.sl.TZ0.6c
| Date | November 2018 | Marks available | [Maximum mark: 1] | Reference code | 18N.2.sl.TZ0.6c |
| Level | sl | Paper | 2 | Time zone | TZ0 |
| Command term | State | Question number | c | Adapted from | N/A |
c.
[Maximum mark: 1]
18N.2.sl.TZ0.6c
Butanoic acid, CH3CH2CH2COOH, is a weak acid and ethylamine, CH3CH2NH2, is a weak base.
(c)
State the formula of the salt formed when butanoic acid reacts with ethylamine.
[1]
Markscheme
CH3CH2NH3+ CH3CH2CH2COO−
OR
CH3CH2CH2COO− CH3CH2NH3+
OR
CH3CH2CH2COO− H3N+CH2CH3 ✔
The charges are not necessary for the mark.
