DP Chemistry (last assessment 2024)

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Question 18N.2.sl.TZ0.a

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Date November 2018 Marks available [Maximum mark: 2] Reference code 18N.2.sl.TZ0.a
Level sl Paper 2 Time zone TZ0
Command term State Question number a Adapted from N/A
a.
[Maximum mark: 2]
18N.2.sl.TZ0.a

Butanoic acid, CH3CH2CH2COOH, is a weak acid and ethylamine, CH3CH2NH2, is a weak base.

State the equation for the reaction of each substance with water.

[2]

Markscheme

Butanoic acid:
CH3CH2CH2COOH (aq) + H2O (l) ⇌ CH3CH2CH2COO− (aq) + H3O+ (aq) ✔

 

Ethylamine:
CH3CH2NH2 (aq) + H2O (l) ⇌ CH3CH2NH3+ (aq) + OH− (aq) ✔

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