Question 19M.3.HL.TZ2.8
| Date | May 2019 | Marks available | [Maximum mark: 5] | Reference code | 19M.3.HL.TZ2.8 |
| Level | HL | Paper | 3 | Time zone | TZ2 |
| Command term | Calculate, Define, Determine | Question number | 8 | Adapted from | N/A |
A proton has a total energy 1050 MeV after being accelerated from rest through a potential difference V.
Define total energy.
[1]
total energy is the sum of the rest energy and the kinetic energy ✔
Generally well answered by most candidates. A common mistake was to define the total energy in the context of classical mechanics.
Determine the momentum of the proton.
[1]
«p2 c2 = 10502–9382 therefore» p=472«MeVc–1»✔
Most candidates seemed to have the right starting points but mistakes were often made in attempting to convert units. The energy-momentum equation is generally best answered using only ‘MeV’ based units.
Determine the speed of the proton.
[2]
✔
OR
«ms–1» ✔
An easy calculation, that was generally well answered.
Calculate the potential difference V.
[1]
V = 112 «MV» ✔
Very few candidates realised that this question required a simple calculation using eV= KE = (γ-1)E.