DP Physics (last assessment 2024)

Question 19N.3.SL.TZ0.6a(i)

Date	November 2019	Marks available	[Maximum mark: 2]	Reference code	19N.3.SL.TZ0.6a(i)
Level	SL	Paper	3	Time zone	TZ0
Command term	Show that	Question number	a(i)	Adapted from	N/A

a(i).

[Maximum mark: 2]

19N.3.SL.TZ0.6a(i)

An ideal gas consisting of 0.300 mol undergoes a process ABCD. AB is an adiabatic expansion from the initial volume V_A to the volume 1.5 V_A. BC is an isothermal compression. The pressures at C and D are the same as at A.

The following data are available.

Pressure at A = 250 kPa
Volume at C = 3.50 × 10^–3 m³
Volume at D = 2.00 × 10^–3 m³

(a(i))

Show that the pressure at B is about 130 kPa.

[2]

Markscheme

$P_{B} = \frac{250 \times 10^{3}}{1 . 5^{\frac{5}{3}}} « from P_{B} {(1.5 V_{A})}^{\frac{5}{3}} = 250 \times 10^{3} \times {V_{A}}^{\frac{5}{3}} »$ ✔

= 127 kPa ✔

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Option B: Engineering physics

Option B: Engineering physics » Option B: Engineering physics (Core topics) » B.2 – Thermodynamics

Option B: Engineering physics » Option B: Engineering physics (Core topics)

Question 19N.3.SL.TZ0.6a(i)

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