DP Physics (last assessment 2024)
Question 21M.2.SL.TZ1.1d.i
Date | May 2021 | Marks available | [Maximum mark: 2] | Reference code | 21M.2.SL.TZ1.1d.i |
Level | SL | Paper | 2 | Time zone | TZ1 |
Command term | Determine | Question number | d.i | Adapted from | N/A |
d.i.
[Maximum mark: 2]
21M.2.SL.TZ1.1d.i
Two players are playing table tennis. Player A hits the ball at a height of 0.24 m above the edge of the table, measured from the top of the table to the bottom of the ball. The initial speed of the ball is 12.0 m s−1 horizontally. Assume that air resistance is negligible.
The ball bounces and then reaches a peak height of 0.18 m above the table with a horizontal speed of 10.5 m s−1. The mass of the ball is 2.7 g.
(d.i)
Determine the kinetic energy of the ball immediately after the bounce.
[2]
Markscheme
ALTERNATIVE 1
KE = mv2 + mgh = 0.0027 ×10.52 + 0.0027 × 9.8 × 0.18 ✓
0.15 «J» ✓
ALTERNATIVE 2
Use of vx = 10.5 AND vy = 1.88 to get v = «» = 10.67 «m s−1» ✓
KE = × 0.0027 × 10.672 = 0.15 «J» ✓

