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Question 21N.2.HL.TZ0.5d.i

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Date November 2021 Marks available [Maximum mark: 2] Reference code 21N.2.HL.TZ0.5d.i
Level HL Paper 2 Time zone TZ0
Command term Show that Question number d.i Adapted from N/A
d.i.
[Maximum mark: 2]
21N.2.HL.TZ0.5d.i

A square loop of side 5.0 cm enters a region of uniform magnetic field at t = 0. The loop exits the region of magnetic field at t = 3.5 s. The magnetic field strength is 0.94 T and is directed into the plane of the paper. The magnetic field extends over a length 65 cm. The speed of the loop is constant.

(d.i)

Show that the energy dissipated in the loop from t = 0 to t = 3.5 s is 0.13 J.

[2]

Markscheme

Energy is being dissipated for 0.50 s ✓


E=Fvt=1.3×0.20×0.50=«0.13 J»

OR

E=Vlt=0.80×0.33×0.50=«0.13 J» ✓

 

Allow ECF from (b) and (c).

Watch for candidates who do not justify somehow the use of 0.5 s and just divide by 2 their answer.

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