Question 22M.2.SL.TZ1.4a
| Date | May 2022 | Marks available | [Maximum mark: 2] | Reference code | 22M.2.SL.TZ1.4a |
| Level | SL | Paper | 2 | Time zone | TZ1 |
| Command term | Calculate | Question number | a | Adapted from | N/A |
A power supply is connected to three resistors P, Q and R of fixed value and to an ideal voltmeter. A variable resistor S, formed from a solid cylinder of conducting putty, is also connected in the circuit. Conducting putty is a material that can be moulded so that the resistance of S can be changed by re-shaping it.
The resistance values of P, Q and R are 40 Ω, 16 Ω and 60 Ω respectively. The emf of the power supply is 6.0 V and its internal resistance is negligible.
Calculate the potential difference across P.
[2]
ALTERNATIVE 1
attempt to use potential divider equation or similar method ✓
«»= 2.4 «V» ✓
ALTERNATIVE 2
«current = » = 0.06 «A» ✓
40 x 0.06 = 2.4 «V» ✓
This was generally well done at the higher level. Some SL candidates struggled to calculate the correct current but earned the second marking point through ECF.
