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Question 23M.3.HL.TZ1.5

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Date May 2023 Marks available [Maximum mark: 8] Reference code 23M.3.HL.TZ1.5
Level HL Paper 3 Time zone TZ1
Command term Calculate, Comment, Determine, Show that Question number 5 Adapted from N/A
5.
[Maximum mark: 8]
23M.3.HL.TZ1.5

A muon is an unstable particle with a half-life of 1.56 μs as measured in the muon’s rest frame. Muons are produced in a laboratory and are all directed at a speed 0.866c towards a muon detector. The gamma factor (γ) for this speed is 2.00. The detector, according to observers in the laboratory, is a distance D from the muon source.

(a)

According to laboratory observers number of muons detectednumber of muons produced=12.

Calculate D.

[2]

Markscheme

T12 = 2.00 × 1.56 × 10−6 or  3.12 × 10−6 s ✓

D = «3.12 × 10−6 × 0.866 × 3 × 10=» 811 m

 

Award [2] for BCA

Examiners report

Muon. Prepared students were able to distinguish between the rest frame of a muon and the rest frame of the detector, and then apply half time to these frames.

(b)

In the muon source rest frame (frame S), the detector is approaching at a speed 0.866c.

In frame S,

(b.i)

show that the distance travelled by the detector when it meets the muon source is 405 m.

[1]

Markscheme

0.866c × half life = 0.866c × 1.56 × 10−6 = « 405 m»

OR

distance travelled by detector = DyD2 = «405 m» ✓

 

Working must be seen.

(b.ii)

determine the time taken for the detector to reach the muon source.

[1]

Markscheme

transit time = 4050.866c = 1.56 µs

 

Award [1] for BCA.

(c)

Calculate, using the answers to (b)(i) and (b)(ii) the ratio number of muons detectednumber of muons produced in S.

[2]

Markscheme

transit time is one half life ✓

so ratio has to be 12

 

Award [2] for BCA.

(d)

Comment on the ratios in (a) and (c).

[2]

Markscheme

the answers are the same ✓

count rates cannot vary from frame to frame / OWTTE

 

Do not allow ECF from (c).

Award [2] for “count rates cannot vary” if student made a mistake OR no answer in (c) and well discussed here.