DP Physics (last assessment 2024)

Test builder »

Question 23M.3.HL.TZ1.19

Select a Test
Date May 2023 Marks available [Maximum mark: 7] Reference code 23M.3.HL.TZ1.19
Level HL Paper 3 Time zone TZ1
Command term Estimate, Show that, State, Suggest Question number 19 Adapted from N/A
19.
[Maximum mark: 7]
23M.3.HL.TZ1.19
(a)

A spherical nebula has radius 9 × 1015 m and contains 1010 atoms of hydrogen per cubic metre. Show that the mass of the nebula is about 5 × 1031 kg.

[2]

Markscheme

V = 4πR33 «= 4π(9×1015)33 = 3.05 × 1048 m3» ✓

M = 3.05 × 1048 × 1010 × 1.67 × 10−27 = 5.1 × 1031 «kg» ✓

For MP2, values must be substituted to show working.

Examiners report

Collapsed nebula. The calculation of the mass of a sphere of a given radius and density was done well. Also, students worked well with the concept of Jeans mass. 

(b)

The Jeans mass MJ, in kg, for a nebula containing hydrogen at a Kelvin temperature T is given by

MJ=1.8×1033T1001.5

The nebula in (a) has a temperature of 50 K. Suggest why this nebula will not collapse to form a star.

[2]

Markscheme

«MJ=1.8×1033501001.5 =» 6.4 × 1032 kg ✓

according to the Jeans criterion collapse will start when the mass of the star is greater than the Jeans mass✓

«which is not the case here»

(c.i)

The temperature of the nebula is decreasing. Estimate the temperature at which the nebula will begin to collapse.

[2]

Markscheme

1.8×1033T1001.5 = 5.1 × 1031

T ≈ 9 K ✓

(c.ii)

State one condition for the collapsed nebula in (c)(i) to form a star.

[1]

Markscheme

the temperature at the core must be high enough for fusion «of hydrogen» to take place ✓

(d)

The mass of the Sun is 2 × 1030 kg and the Sun will spend 8 × 109 years on the main sequence. The collapsed nebula in (c) also becomes a main sequence star. Estimate the time this star will spend on the main sequence.

Markscheme

M3.5Mt

tt=MM2.5

t = 2×10305×10312.5 × 8 × 109 = 2.6 × 106 years ✓

Award [3] for correct alternative solution OR BCA from interval 2.2 to 2.8.

Examiners report

In d), only the best students correctly calculated the time the star would spend on the main sequence.