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Question 23M.3.SL.TZ1.1

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Date May 2023 Marks available [Maximum mark: 8] Reference code 23M.3.SL.TZ1.1
Level SL Paper 3 Time zone TZ1
Command term Calculate, Deduce, Draw, Estimate, Identify, Suggest Question number 1 Adapted from N/A
1.
[Maximum mark: 8]
23M.3.SL.TZ1.1

A student attaches one end of a copper wire to an oscillator operating at a fixed frequency. The other end of the wire passes over a pulley to weights that hang vertically. The first harmonic standing wave is established by using the slider to change the length of the wire. The procedure is repeated for different weights.

The mass m of the weights and the wavelength λ of the wave are related by

m=μf2gλ2

where μ is a constant, f is the frequency of the wave and g = 9.8 m s−2 .

(a)

Deduce the unit of μ in terms of fundamental SI units.

[1]

Markscheme

[μ] = «kg×ms-2s-2×m2» kg × m−1

 

Accept kg/m.

Do not accept g m−1.

(b)

The graph shows the data obtained by the student, plotted to show the variation of m with λ2.

(b.i)

Draw the line of best fit for these data.

[1]

Markscheme

straight line through all error bars ✓

(b.ii)

Identify the evidence for a systematic error in the data.

[1]

Markscheme

line does not go through the origin «and all error bars» ✓

(b.iii)

Suggest a possible reason for the systematic error.

[1]

Markscheme

mass of tray of weights neglected/friction at pulley/friction at slider/thickness of slider/zero off-set error ✓

 

Do not allow vague answers like friction neglected / error in length measurement.

(b.iv)

Calculate the gradient of the graph.

[2]

Markscheme

large enough triangle Δm ≥ 50 g✓

answer in range 0.210 − 0.240 «kg m−1» ✓

 

Accept answers in g m−2.

Do not allow ECF from MP1.

(c)

The percentage uncertainty of the gradient is 6.0 %. The frequency f of the wave is (60.0 ± 2.0 %) Hz.

Estimate, using the answer to (b)(iv), μ for the string. Include the percentage uncertainty of μ in your answer.

[2]

Markscheme

μ = «g×gradientf2» = 6.229 × 10−4 «kg × m−1»

percentage uncertainty = 6.0 + 2 × 2.0 = 10 % ✓

 

Accept μ in the range 5.7 to 6.6.

Allow answer in g m−1 .

Allow ECF from (b).