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Question 18M.3.SL.TZ1.8a.ii

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Date May 2018 Marks available [Maximum mark: 3] Reference code 18M.3.SL.TZ1.8a.ii
Level SL Paper 3 Time zone TZ1
Command term Calculate Question number a.ii Adapted from N/A
a.ii.
[Maximum mark: 3]
18M.3.SL.TZ1.8a.ii

A converging (convex) lens forms an image of an object on a screen.

(a.ii)

The lens is 18 cm from the screen and the image is 0.40 times smaller than the object. Calculate the power of the lens, in cm–1. 

[3]

Markscheme

« − 18 u = − 0.40 »

u = 45

1 45 + 1 18 = 1 f

OR

f = 13 «cm»

P =  1 f = « 1 13 » = 0.078 «cm–1»

 

Accept answer 7.7«D».

[3 marks]

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