DP Physics (last assessment 2024)

Question 18M.2.SL.TZ2.1b

Date	May 2018	Marks available	[Maximum mark: 4]	Reference code	18M.2.SL.TZ2.1b
Level	SL	Paper	2	Time zone	TZ2
Command term	Determine	Question number	b	Adapted from	N/A

[Maximum mark: 4]

18M.2.SL.TZ2.1b

(b)

The radius of the bowl is 8.0 m and θ = 22°. Determine the speed of the ball.

[4]

Markscheme

$\frac{{mg}}{{\tan \theta }}$ = m $\frac{{{v^2}}}{r}$

r = R cos θ

v = $\sqrt {\frac{{gR{{\cos }^2}\theta }}{{\sin \theta }}} /\sqrt {\frac{{gR\cos \theta }}{{\tan \theta }}} /\sqrt {\frac{{9.81 \times 8.0\cos 22}}{{\tan 22}}}$

v = 13.4/13 «ms ^–¹»

Award [4] for a bald correct answer

Award [3] for an answer of 13.9/14 «ms ^–¹». MP2 omitted

[4 marks]

Syllabus sections

Core

Core » Topic 2: Mechanics » 2.2 – Forces

Core » Topic 2: Mechanics

Question 18M.2.SL.TZ2.1b

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