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Question 18M.2.HL.TZ1.3

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Date May 2018 Marks available [Maximum mark: 13] Reference code 18M.2.HL.TZ1.3
Level HL Paper 2 Time zone TZ1
Command term Calculate, Deduce, Explain, Outline Question number 3 Adapted from N/A
3.
[Maximum mark: 13]
18M.2.HL.TZ1.3

A beam of coherent monochromatic light from a distant galaxy is used in an optics experiment on Earth.

The beam is incident normally on a double slit. The distance between the slits is 0.300 mm. A screen is at a distance D from the slits. The diffraction angle θ is labelled.

M18/4/PHYSI/SP2/ENG/TZ1/03.a

(a.i)

A series of dark and bright fringes appears on the screen. Explain how a dark fringe is formed.

[3]

Markscheme

superposition of light from each slit / interference of light from both slits

with path/phase difference of any half-odd multiple of wavelength/any odd multiple of π  (in words or symbols)

producing destructive interference

 

Ignore any reference to crests and troughs.

[3 marks]

A beam of coherent monochromatic light from a distant galaxy is used in an optics experiment on Earth.

The beam is incident normally on a double slit. The distance between the slits is 0.300 mm. A screen is at a distance D from the slits. The diffraction angle θ is labelled.

M18/4/PHYSI/SP2/ENG/TZ1/03.a

(a.ii)

Outline why the beam has to be coherent in order for the fringes to be visible.

[1]

Markscheme

light waves (from slits) must have constant phase difference / no phase difference / be in phase

 

OWTTE

[1 mark]

(a.iii)

The wavelength of the beam as observed on Earth is 633.0 nm. The separation between a dark and a bright fringe on the screen is 4.50 mm. Calculate D.

[2]

Markscheme

evidence of solving for «D = s d λ » ✔

« 4.50 × 10 3 × 0.300 × 10 3 633.0 × 10 9 × 2 » = 4.27 «m» ✔

 

Award [1] max for 2.13 m.

The graph of variation of intensity with diffraction angle for this experiment is shown.

M18/4/PHYSI/HP2/ENG/TZ1/03.b

(b.i)

Calculate the angular separation between the central peak and the missing peak in the double-slit interference intensity pattern. State your answer to an appropriate number of significant figures.

[3]

Markscheme

sin θ 4 × 633.0 × 10 9 0.300 × 10 3

sin θ = 0.0084401…

final answer to three sig figs (eg 0.00844 or 8.44 × 10–3)

 

Allow ECF from (a)(iii).

Award [1] for 0.121 rad (can award MP3 in addition for proper sig fig)

Accept calculation in degrees leading to 0.481 degrees.

Award MP3 for any answer expressed to 3sf.

[3 marks]

(b.ii)

Deduce, in mm, the width of one slit.

[2]

Markscheme

use of diffraction formula «b = λ θ »

OR

633.0 × 10 9 0.00844

«=» 7.5«00» × 10–2 «mm»

 

Allow ECF from (b)(i).

[2 marks]

(c)

The wavelength of the light in the beam when emitted by the galaxy was 621.4 nm.

Explain, without further calculation, what can be deduced about the relative motion of the galaxy and the Earth.

[2]

Markscheme

wavelength increases (so frequency decreases) / light is redshifted

galaxy is moving away from Earth

 

Allow ECF for MP2 (ie wavelength decreases so moving towards).

[2 marks]