DP Physics (last assessment 2024)
Question 18M.2.HL.TZ1.8b.i
Date | May 2018 | Marks available | [Maximum mark: 2] | Reference code | 18M.2.HL.TZ1.8b.i |
Level | HL | Paper | 2 | Time zone | TZ1 |
Command term | Calculate | Question number | b.i | Adapted from | N/A |
b.i.
[Maximum mark: 2]
18M.2.HL.TZ1.8b.i
Hydrogen atoms in an ultraviolet (UV) lamp make transitions from the first excited state to the ground state. Photons are emitted and are incident on a photoelectric surface as shown.
The photons cause the emission of electrons from the photoelectric surface. The work function of the photoelectric surface is 5.1 eV.
(b.i)
Calculate, in J, the maximum kinetic energy of the emitted electrons.
[2]
Markscheme
10 – 5.1 = 4.9 «eV»
4.9 × 1.6 × 10–19 = 7.8 × 10–19 «J»
Allow 5.1 if 10.2 is used to give 8.2×10−19 «J».
