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Question 18M.2.HL.TZ2.9d.iii

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Date May 2018 Marks available [Maximum mark: 2] Reference code 18M.2.HL.TZ2.9d.iii
Level HL Paper 2 Time zone TZ2
Command term Calculate Question number d.iii Adapted from N/A
d.iii.
[Maximum mark: 2]
18M.2.HL.TZ2.9d.iii

Rhodium-106 ( 45 106 Rh ) decays into palladium-106 ( 46 106 Pd ) by beta minus (β–) decay. The diagram shows some of the nuclear energy levels of rhodium-106 and palladium-106. The arrow represents the β– decay.

M18/4/PHYSI/HP2/ENG/TZ2/09.d

(d.iii)

Calculate the wavelength of the gamma ray photon in (d)(ii).

[2]

Markscheme

Photon energy

E = 0.48 × 106 × 1.6 × 10–19 = «7.68 × 10–14 J»

λ = « h c E = 6.63 × 10 − 34 × 3 × 10 8 7.68 × 10 − 14 =» 2.6 × 10–12 «m»

 

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Allow ECF from incorrect energy

[2 marks]

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