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Question 18N.2.HL.TZ0.3b.ii

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Date November 2018 Marks available [Maximum mark: 4] Reference code 18N.2.HL.TZ0.3b.ii
Level HL Paper 2 Time zone TZ0
Command term Determine Question number b.ii Adapted from N/A
b.ii.
[Maximum mark: 4]
18N.2.HL.TZ0.3b.ii

A chicken’s egg of mass 58 g is dropped onto grass from a height of 1.1 m. Assume that air resistance is negligible and that the egg does not bounce or break.

(b.ii)

The egg comes to rest in a time of 55 ms. Determine the magnitude of the average decelerating force that the ground exerts on the egg.

[4]

Markscheme

ALTERNATIVE 1:

initial momentum = mv =  2 × 0.058 × 0.63  «= 0.27 kg m s−1»

OR

mv =  0.058 × 2 × 9.81 × 1.1  «= 0.27 kg m s−1» ✔

force = « change in momentum time =»  0.27 0.055  ✔

4.9 «N» ✔

F − mg = 4.9 so F = 5.5 «N» ✔

 

ALTERNATIVE 2:

«Ek = 1 2 mv2 = 0.63 J» v = 4.7 m s−1 ✔

acceleration = « Δ v Δ t =»  4.7 55 × 10 − 3 = «85 m s−2» ✔

4.9 «N» ✔

F − mg = 4.9 so F= 5.5 «N» ✔

 

Accept negative acceleration and force.

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