DP Physics (last assessment 2024)

Question 18N.3.SL.TZ0.6c.i

Date	November 2018	Marks available	[Maximum mark: 3]	Reference code	18N.3.SL.TZ0.6c.i
Level	SL	Paper	3	Time zone	TZ0
Command term	Show that	Question number	c.i	Adapted from	N/A

c.i.

[Maximum mark: 3]

18N.3.SL.TZ0.6c.i

A uniform rod of weight 36.0 N and length 5.00 m rests horizontally. The rod is pivoted at its left-hand end and is supported at a distance of 4.00 m from the frictionless pivot.

(c.i)

At the instant the rod becomes vertical show that the angular speed is ω = 2.43 rad s^–1.

[3]

Markscheme

«from conservation of energy» Change in GPE = Change in rotational KE ✔

$W\frac{L}{2} = \frac{1}{2}I{\omega ^2}$ ✔

$\omega = \sqrt {\frac{{36.0 \times 5.00}}{{30.6}}}$ ✔

«ω = 2.4254 rad s^–1»

Syllabus sections

Option B: Engineering physics

Option B: Engineering physics » Option B: Engineering physics (Core topics) » B.1 – Rigid bodies and rotational dynamics

Option B: Engineering physics » Option B: Engineering physics (Core topics)

Question 18N.3.SL.TZ0.6c.i

Select a Test

Syllabus sections

Confirm action