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Question 18N.3.SL.TZ0.7a.ii

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Date November 2018 Marks available [Maximum mark: 2] Reference code 18N.3.SL.TZ0.7a.ii
Level SL Paper 3 Time zone TZ0
Command term Show that Question number a.ii Adapted from N/A
a.ii.
[Maximum mark: 2]
18N.3.SL.TZ0.7a.ii

The pV diagram of a heat engine using an ideal gas consists of an isothermal expansion A → B, an isobaric compression B → C and an adiabatic compression C → A.

The following data are available:

Temperature at A   = 385 K

Pressure at A         = 2.80 × 106 Pa

Volume at A           = 1.00 × 10–4 m3

Volume at B           = 2.80 × 10–4 m3

Volume at C           = 1.85 × 10–4 m3

(a.ii)

Show that at C the temperature is 254 K.

[2]

Markscheme

ALTERNATIVE 1:

Since TB = TA then Tc =  V c T B V B ✔

 =  1.85 × 385 2.8 «= 254.4 K» ✔

 

ALTERNATIVE 2:

2.80 × 1.00 385 = 1.00 × 1.85 T c «K»✔

T c = 385 × 1.00 × 1.85 2.80 «= 254.4 K» ✔

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