DP Physics (last assessment 2024)

Test builder »

Question 18N.3.HL.TZ0.6b.ii

Select a Test
Date November 2018 Marks available [Maximum mark: 2] Reference code 18N.3.HL.TZ0.6b.ii
Level HL Paper 3 Time zone TZ0
Command term Calculate Question number b.ii Adapted from N/A
b.ii.
[Maximum mark: 2]
18N.3.HL.TZ0.6b.ii

An electron with total energy 1.50 MeV collides with a positron at rest. As a result two photons are produced. One photon moves in the same direction as the electron and the other in the opposite direction.

The momenta of the photons produced have magnitudes p1 and p2. A student writes the following correct equations.

p1 – p2 = 1.41 MeV c–1

p1 + p2 = 2.01 MeV c–1

(b.ii)

Calculate, in MeV c–1, p1 and p2.

[2]

Markscheme

adding 2p1 = 3.42 MeV c–1 ⇒ p1 = 1.17 MeV c–1 ✔

p2 = 0.30 MeV c–1 ✔

Syllabus sections