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Question 19M.2.HL.TZ2.5bii

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Date May 2019 Marks available [Maximum mark: 2] Reference code 19M.2.HL.TZ2.5bii
Level HL Paper 2 Time zone TZ2
Command term Calculate Question number bii Adapted from N/A
bii.
[Maximum mark: 2]
19M.2.HL.TZ2.5bii

A proton moves along a circular path in a region of a uniform magnetic field. The magnetic field is directed into the plane of the page.

The speed of the proton is 2.16 × 106 m s-1 and the magnetic field strength is 0.042 T.

(bii)

For this proton, calculate, in s, the time for one full revolution.

[2]

Markscheme

T = 2 π R v / 2 π × 0.54 2.16 × 10 6  ✔

T = 1.6 × 10 − 6 «s»   ✔

Examiners report

This was well answered with many candidates scoring ECF from the previous part.

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