DP Physics (last assessment 2024)
Question 19M.3.HL.TZ2.8a
| Date | May 2019 | Marks available | [Maximum mark: 1] | Reference code | 19M.3.HL.TZ2.8a |
| Level | HL | Paper | 3 | Time zone | TZ2 |
| Command term | Define | Question number | a | Adapted from | N/A |
a.
[Maximum mark: 1]
19M.3.HL.TZ2.8a
A proton has a total energy 1050 MeV after being accelerated from rest through a potential difference V.
(a)
Define total energy.
[1]
Markscheme
total energy is the sum of the rest energy and the kinetic energy ✔
Examiners report
Generally well answered by most candidates. A common mistake was to define the total energy in the context of classical mechanics.
