DP Physics (last assessment 2024)
Question 19M.3.HL.TZ2.8biii
| Date | May 2019 | Marks available | [Maximum mark: 1] | Reference code | 19M.3.HL.TZ2.8biii |
| Level | HL | Paper | 3 | Time zone | TZ2 |
| Command term | Calculate | Question number | biii | Adapted from | N/A |
biii.
[Maximum mark: 1]
19M.3.HL.TZ2.8biii
A proton has a total energy 1050 MeV after being accelerated from rest through a potential difference V.
(biii)
Calculate the potential difference V.
[1]
Markscheme
V = 112 «MV» ✔
Examiners report
Very few candidates realised that this question required a simple calculation using eV= KE = (γ-1)E.
