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Question 19M.3.SL.TZ2.8b

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Date May 2019 Marks available [Maximum mark: 2] Reference code 19M.3.SL.TZ2.8b
Level SL Paper 3 Time zone TZ2
Command term Calculate Question number b Adapted from N/A
b.
[Maximum mark: 2]
19M.3.SL.TZ2.8b

A uniform ladder of weight 50.0 N and length 4.00 m is placed against a frictionless wall making an angle of 60.0° with the ground.

(b)

Calculate F.

[2]

Markscheme

«clockwise moments = anticlockwise moments»

50 × 2cos 60 = NW × 4sin 60 ✔

« N W = F = 50 × 2 cos ⁡ 60 4 sin ⁡ 60 »

F = 14.4«N» ✔

Examiners report

Very few candidates could take moments about any point and correct answers were rare both at SL and HL.

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