DP Physics (last assessment 2024)

Question 19M.3.HL.TZ2.bi

Date	May 2019	Marks available	[Maximum mark: 1]	Reference code	19M.3.HL.TZ2.bi
Level	HL	Paper	3	Time zone	TZ2
Command term	Show that	Question number	bi	Adapted from	N/A

bi.

[Maximum mark: 1]

19M.3.HL.TZ2.bi

The graph shows a received signal incident upon a transducer to produce an A-scan. The density of the soft tissue being examined is approximately 1090 kg m^-3.

The acoustic impedance of soft tissue is 1.65 × 106 kg m^-2 s^-1. Show that the speed of sound in the soft tissue is approximately 1500 m s^–1.

[1]

Markscheme

$c = « \frac{Z}{\rho } = \frac{{1.65 \times {{10}^6}}}{{1090{\text{kg}}{{\text{m}}^{ - 3}}}} =» 1514$ «ms^–1» ✔

«≈1500ms^–1»

Answer 1500 is given, check working or look for at least 3 significant figures.

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Option C: Imaging

Option C: Imaging » Option C: Imaging (Additional higher level option topics) » C.4 – Medical imaging (HL only)

Option C: Imaging » Option C: Imaging (Additional higher level option topics)

Question 19M.3.HL.TZ2.bi

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