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Question 19N.3.SL.TZ0.4c(iv)

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Date November 2019 Marks available [Maximum mark: 2] Reference code 19N.3.SL.TZ0.4c(iv)
Level SL Paper 3 Time zone TZ0
Command term Determine Question number c(iv) Adapted from N/A
c(iv).
[Maximum mark: 2]
19N.3.SL.TZ0.4c(iv)

A train is moving across a bridge with a speed v = 0.40c. Observer A is at rest in the train. Observer B is at rest with respect to the bridge.

The length of the bridge LB according to observer B is 2.0 km.

According to observer B, two lamps at opposite ends of the bridge are turned on simultaneously as observer A crosses the bridge. Event X is the lamp at one end of the bridge turning on. Event Y is the lamp at the other end of the bridge turning on.

Events X and Y are shown on the spacetime diagram. The space and time axes of the reference frame for observer B are x and ct. The line labelled ct' is the worldline of observer A.

(c(iv))

Determine the time, according to observer A, between X and Y.

[2]

Markscheme

ALTERNATIVE 1

t'=1.09×0-0.4×2.0×1033.0×108 

= «–»2.9 × 10–6 «s» ✔

 

ALTERNATIVE 2

equating spacetime intervals between X and Y

relies on realization that x'=γx-0  eg: 

ct'2-1.09×20002=02-20002

t'=«±»1.09×20002-200023.0×108=«±»2.9×10-6 «s» ✔

 

ALTERNATIVE 3

use of diagram from answer to 4(c)(ii) (1 small square = 200 m)

counts 4.5 to 5 small squares (allow 900 – 1000 m) between events for A seen on B’s ct axis ✔

950γc=2.9×10-6±0.2×10-6 «s» ✔