DP Physics (last assessment 2024)

Question 20N.3.HL.TZ0.b

Date	November 2020	Marks available	[Maximum mark: 2]	Reference code	20N.3.HL.TZ0.b
Level	HL	Paper	3	Time zone	TZ0
Command term	Calculate	Question number	b	Adapted from	N/A

[Maximum mark: 2]

20N.3.HL.TZ0.b

A deuterium $({}_{1}^{2}H)$ nucleus (rest mass $2.014 u$ ) is accelerated by a potential difference of $2.700 \times 10^{2} MV$ .

Calculate the total energy of the deuterium particle in $MeV$ .

[2]

Markscheme

«rest energy =» $(2.014 \times 931.5) « MeV »$ ✓

$« E_{T} = KE + rest energy = 270.0 + (2.014 \times 931.5) = » 2146 « MeV »$ ✓

Final answer accept $3.443 \times 10^{- 10} J$ if unit given

Award [2] marks for a bald correct answer.

Examiners report

Most were able to score full marks. A few candidates messed up by trying to convert to J, although some were successful with this additional difficulty.

Syllabus sections

Option A: Relativity

Option A: Relativity » Option A: Relativity (Additional higher level option topics) » A.4 – Relativistic mechanics (HL only)

Option A: Relativity » Option A: Relativity (Additional higher level option topics)

Question 20N.3.HL.TZ0.b

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